The gas law is only accurate for systems which are in thermodynamic equilibrium.This system is not in a state of equilibrium.
The steam is not only "spreading out", it is also moving en masse in one direction. harry > >From: Stephen A. Lawrence <[email protected]> >To: [email protected] >Sent: Tue, February 8, 2011 3:56:49 PM >Subject: Re: [Vo]:Re: Levi's interpretation of the two Rossi demos does not >hold >water, decisive critique by Joshua Cude: Rich Murray 2011.02.08 > > > >On 02/08/2011 03:43 PM, Harry Veeder wrote: >stephen, the steam does absorb more energy, but this manifests as a faster >flow >of steam rather than as a temperature increase. >> No. Remember, PV = nRT for steam, just like any reasonable gas. That means, V = nRT/P If the steam flow accelerates with no change in pressure, and the diameter of the pipe is uniform, then its volume must be increasing as it moves along the pipe -- the steam is "spreading out" in the pipe. If its volume is increasing while pressure is constant, and nobody's adding more water vapor (so moles per second coming out the end of the pipe is constant), then its temperature must be increasing. And note -- the number of moles per second, n/time, is fixed by the constant displacement pump. QED. ________________________________ Incidentally, what happens if we turn up the pump rate just a little? Either (a) the thing starts spewing water, because the water no longer boils, or (b) the power level increases. Similarly, what happens if we turn *down* the water pump rate just a little? If the temperature doesn't suddenly start taking off, then the power level must have dropped. If the results of the test didn't depend, very critically, on the exact rate at which the pump was running, what can we conclude? Whoa, nelly! The power output is controlled by the water pump!
