On Apr 12, 2011, at 3:22 PM, mix...@bigpond.com wrote:
In reply to Horace Heffner's message of Tue, 12 Apr 2011 13:41:19
-0800:
Hi,
[snip]
This roughly 0.8 MeV energy comes from the kinetic energy of the
electron, which is the same high value it had in the very small
deflated state
The kinetic energy of the electron in the deflated state comes from
the
potential energy it had relative to the proton in the non-deflated
state. Since
the total mass energy of a Hydrogen atom is short of the energy
required to form
a neutron by 800 keV, that is still so in the deflated state. IOW
the kinetic
energy of the electron is 800 keV less than would be needed to form
a neutron.
Regards,
Robin van Spaandonk
http://rvanspaa.freehostia.com/Project.html
Not true. The kinetic energy of the electron in the deflated state
can be around 1 MeV. In that case the potential energy is about -1
MeV. Upon fusion with Ni, the kinetic energy in that case remains
initially at 1 MeV, but, due to the suddenly present 28 extra Ni
nucleus charges, the potential energy is reduced to -29 Mev, and the
net potential plus kinetic energy is reduced by 28 MeV. This loss of
potential energy does not prevent electron capture of the now
energetically trapped electron, if it occurs very fast, because that
electron still has the kinetic energy necessary. I think it is also
true that nuclear heat may prolong the ability of the electron to
both radiate and be captured. Nuclear heat to which I refer is
provided by zero point energy, in a manner as described here:
http://mtaonline.net/~hheffner/NuclearZPEtapping.pdf
in which I estimate the nuclear temperature for Ni to be 1.02 MeV.
This then provides a method of capturing zero point energy.
Best regards,
Horace Heffner
http://www.mtaonline.net/~hheffner/
