On Apr 12, 2011, at 8:53 PM, [email protected] wrote:
In reply to Horace Heffner's message of Tue, 12 Apr 2011 15:38:07
-0800:
Hi,
[snip]
On Apr 12, 2011, at 3:22 PM, [email protected] wrote:
In reply to Horace Heffner's message of Tue, 12 Apr 2011 13:41:19
-0800:
Hi,
[snip]
This roughly 0.8 MeV energy comes from the kinetic energy of the
electron, which is the same high value it had in the very small
deflated state
The kinetic energy of the electron in the deflated state comes from
the
potential energy it had relative to the proton in the non-deflated
state. Since
the total mass energy of a Hydrogen atom is short of the energy
required to form
a neutron by 800 keV, that is still so in the deflated state. IOW
the kinetic
energy of the electron is 800 keV less than would be needed to form
a neutron.
Regards,
Robin van Spaandonk
http://rvanspaa.freehostia.com/Project.html
Not true. The kinetic energy of the electron in the deflated state
can be around 1 MeV.
That what I just said ;) (Well 7-800 keV anyway). My point was,
that this still
isn't enough to create a free neutron, because the kinetic energy
was subtracted
from the ponderable mass of the H atom. IOW it's not 'extra'.
Again, you are assuming everything adds up. This is not the case,
not momentarily, not longer term. That energy is available as
"extra" energy, at least momentarily.
The 1 MeV kinetic energy I suggested above is actual kinetic energy,
resulting in an actual electron velocity (in a deterministic
interpretation anyway). It represents not energy subtracted from the
mass of the hydrogen, but rather energy obtained from the hydrogen's
field energy, which has no mass. The potential energy lost by
wavefunction collapse of the deflated hydrogen upon the Ni nucleus is
28 times larger than the 1 MeV kinetic energy. Losing 0.8 MeV of the
the 1 MeV kinetic energy is a small issue. It only adds 0.8 MeV to a
28 MeV deficit, which can not be made up even long term with the
fusion energy. This does not mean, however, that the electron has no
initial kinetic energy post fusion, nor that the externally available
reaction enthalpy is zero.
I have sent a separate post describing how I see energy transactions
with the vacuum occurring in deflation fusion. There is no
appearance provided by nature in this case that mass/energy is
conserved. I hope it is clear enough to follow.
However it's not
necessary to create a free neutron anyway, because the neutron
required will be
in a nucleus, and neutrons in nuclei weigh less than free neutrons
anyway
Yes, or at least that is the net effect due to the binding energies,
both strong force and EM.
(by
about 5-10 MeV/c^2, depending on the nucleus).
Best regards,
Horace Heffner
http://www.mtaonline.net/~hheffner/
