On Thu, Jun 23, 2011 at 3:50 PM, Abd ul-Rahman Lomax <[email protected]>wrote:
> At 02:58 PM 6/23/2011, Joshua Cude wrote: > >> But still, you've identified a way the steam could be dry and still pinned >> to the boiling point. Unfortunately, evidence that it *is* dry is still >> absent. And in the Krivit video, the feeble puff of steam at the output is >> pretty good evidence that most of the liquid does not change phase. >> > > Not actually. There will be reduction in steam output due to cooling in the > hose. It's to be expected. The question is how much. And I'm suspicious of > all the ad-hoc calculations. The whole point of a conclusive demo is to make > such calculations as simple as possible > > Basically, assume 750 W of input power, how much steam would be expected > *at the end of a three meter hose* like that. My sense is, not a whole lot! > My guess is that we might not see anything except a little mist. > > But it's a guess. > If all of the claimed input water were converted to steam, that would represent 5 kW of power. At least 3 kW, and probably closer to 4 kW would escape that hose as steam enthalpy. It is clear that what escapes that hose is not even half that, maybe not even a quarter that. So, that means, as I said above, that most of the liquid does not change phase. The steam must be very wet. Actually. Try to think of a 1.5 kW space heater. Do you really think that 3 1-ft diameter turns of a rubber hose at 100C would throw that much heat. It's completely implausible.
