In reply to Jones Beene's message of Wed, 17 Aug 2011 07:39:52 -0700: Hi, [snip] >Potassium is perhaps the most mentioned candidate in the papers, but the >first two IP electrons are at 4.34 and 31.63 eV. What this means >essentially is that the hole only appears when the K(2+) ion takes back the >least energetic of the two electrons lost - the difference being 27.29 eV or >.09 on the high side. That variance does not seem extremely close, really - >and the way it materializes is convoluted - yet it is the most often used >catalyst. This is one of the many reasons that skeptic love to berate >Randell Mills.
The sum of the first three ionization energies of K is 81.6857 eV which is also a good match for m=3. Since this only requires 1 K atom be involved, rather than a three body collision involving H, K and K++, I suspect it is much more likely. > >Strontium is interesting, as it turns up in several important papers, but >since the first 3 electrons go at 5.69, 11.03, and 42.89 eV there is no >obvious fit at all. I have a third ionization energy of 43.6 which gives:- 11.03 + 43.60 = 54.63. Not a bad match for m=2. (11.03 + 42.89 = 53.92 also not too bad). This is also a normal two body reaction, i.e. H + Sr+. (It only requires that Sr++ have picked up one electron already). [snip] Regards, Robin van Spaandonk http://rvanspaa.freehostia.com/project.html
