Hi, Minor correction.
On 3-10-2011 18:38, Man on Bridges wrote:
True, and that's also the reason why only MTBF (Mean Time Between Failure) is used for critical parts, systems, etc. for military vehicles, aircraft and spacecraft. So a MTBF for a vehicle of once in 1 year could statistically result with P = 1-q^n in 1-(1-(1/MTBF))^M = 1-(1-(3600*24*365))^10,000,000 = 0,2717 or 27,17 % total failure once a year.
True, and that's also the reason why only MTBF (Mean Time Between Failure) is used for critical parts, systems, etc. for military vehicles, aircraft and spacecraft. So a MTBF for a vehicle of once in 1 year could statistically result with P = 1-q^n in 1-(1-(1/MTBF))^M = 1-(1-(*1/*3600*24*365))^10,000,000 = 0,2717 or 27,17 % total failure once a year.
Kind regards, MoB
