Dr. K said: "... although I'm not sure that we _all_ glow!" I agree... some are just the black-light of the flock! :-)
And no, I don't think Dr.Mills has ever posted here, however, there is someone who does that keeps close tabs on what Mills is doing... -Mark -----Original Message----- From: Dr Josef Karthauser [mailto:[email protected]] Sent: Tuesday, October 04, 2011 10:43 PM To: [email protected] Subject: Re: [Vo]: Another advancement toward an atomic 'strobe-light'... I doubt he does. (Has he ever posted here?) I like the play on words, although I'm not sure that we _all_ glow! (Well, not all the time, anyway!) :) Joe On 4 Oct 2011, at 08:41, Mark Iverson-ZeroPoint wrote: > Hi Dr. K, > > Yes, I'm sure Dr. Mills will object... > *IF* he ever bothered to read this bunch of loomies! > > Oh, and that's loomies, as in, 'Luminaries'! :-) > > -Mark > > -----Original Message----- > From: Dr Josef Karthauser [mailto:[email protected]] > Sent: Monday, October 03, 2011 11:01 PM > To: [email protected] > Cc: [email protected] > Subject: Re: [Vo]: Another advancement toward an atomic 'strobe-light'... > > On 23 Sep 2011, at 23:23, [email protected] wrote: > >> In reply to Mark Iverson-ZeroPoint's message of Fri, 23 Sep 2011 01:07:14 >> -0700: >> Hi, >> [snip] >>> What are the ends of the dipole? Getting back to the above paragraph of > just what's oscillating. and the aether being under tremendous > stress/tension, perhaps one end of the dipole is a region of higher > pressure, the other, lower pressure. These regions cause the surrounding > aether to 'polarize' in some manner which helps to contain the regions from > expanding or contracting infinitely, and thus, dissipating. Just looking at > one side of the dipole, at >> >> When a free electron binds to a free proton in the ground state, 13.6 eV > is >> released as photon(s), so the ground state is "down" 13.6 eV. This is > -27.2 eV >> electrostatic (potential) energy, and +13.6 eV kinetic energy. The > farthest >> possible extent of the electron occurs when that remaining 13.6 eV of > kinetic >> energy is converted to electrostatic energy, and the electron has no > kinetic >> energy. This happens at twice the Bohr radius, which is thus the maximum >> separation distance between electron and proton. In short the chance that > the >> electron will be found beyond this is zero (unless it acquires energy from >> elsewhere). > > Of course Randell Mills will argue against this, right? > > Joe > >
