On 23 Sep 2011, at 23:23, mix...@bigpond.com wrote: > In reply to Mark Iverson-ZeroPoint's message of Fri, 23 Sep 2011 01:07:14 > -0700: > Hi, > [snip] >> What are the ends of the dipole? Getting back to the above paragraph of >> just what’s oscillating… and the aether being under tremendous >> stress/tension, perhaps one end of the dipole is a region of higher >> pressure, the other, lower pressure. These regions cause the surrounding >> aether to ‘polarize’ in some manner which helps to contain the regions from >> expanding or contracting infinitely, and thus, dissipating. Just looking at >> one side of the dipole, at > > When a free electron binds to a free proton in the ground state, 13.6 eV is > released as photon(s), so the ground state is "down" 13.6 eV. This is -27.2 eV > electrostatic (potential) energy, and +13.6 eV kinetic energy. The farthest > possible extent of the electron occurs when that remaining 13.6 eV of kinetic > energy is converted to electrostatic energy, and the electron has no kinetic > energy. This happens at twice the Bohr radius, which is thus the maximum > separation distance between electron and proton. In short the chance that the > electron will be found beyond this is zero (unless it acquires energy from > elsewhere).
Of course Randell Mills will argue against this, right? Joe
