In reply to Robert Leguillon's message of Thu, 6 Oct 2011 19:19:37 -0500: Hi, [snip] >1 MW is used as a measure of power transfer. The velocity of steam, through a >given opening, produced by 1 MW cannot be calculated; too few required >variables are populated. >You would have to know beginning and ending temperatures, to calculate >required water or steam. If you start with 1 degree C water, or end with 250 >degree C steam, this would effect the required fluid quantities to consume 1 >MW.
Only slightly. At that temperature most of the energy (and hence power) is in the steam. All I did was use d(Volume)/dt = power/pressure, to calculate d(Volume)/dt, then divided by the area of the pipe cross section to get a velocity. I suspect the original author did something similar. > > >[email protected] wrote: > >>In reply to Akira Shirakawa's message of Thu, 06 Oct 2011 11:43:40 +0200: >>Hi, >>[snip] >>>On 2011-10-04 19:18, Akira Shirakawa wrote: >>>> Hello group, >>> >>>More from New Energy Times on this matter: >>> >>>http://blog.newenergytimes.com/2011/10/06/nasa-wont-confirm-relationship-with-rossi-2/ >> >>"?You can?t deliver one megawatt of steam through a 2½-inch pipe unless you go >>hypersonic,? the expert said. >> >>So observers of the big 1 megawatt demonstration that Rossi promised for >>October >>should look for steam exiting the shipping container in excess of 768 mph." >> >>Surely this is only true if the pipe is opened to the air. If the steam >>remains >>under pressure (and e.g. drives a turbine), then it need not be hypersonic, if >>I'm not mistaken. (e.g. at 84 atm the speed would only be 83 mph). >>Regards, >> >>Robin van Spaandonk >> >>http://rvanspaa.freehostia.com/project.html >> >> Regards, Robin van Spaandonk http://rvanspaa.freehostia.com/project.html
