On Oct 14, 2011, at 2:39 AM, [email protected] wrote:
I condensed my thoughts about this into a Youtube video:
http://youtu.be/mSyeJa7a3AE
Explanation in technical terms:
==========================
Primary steam inlet and secondary (warm) water outlet are in direct
thermal contact via the brass tube.
Because thermal flow behaves like electrical current in ohmic
resistive material - it superimposes linear- there must be a
temperature gradient.
Of course I dont know how thick the brass is, it has without doubt
strong coupling to the water. Because the tube is symmetric, there
must be a temperature of 65° [(100+30)/2=65] in the middle symmetry
point if one end has 100° and the other has 30°.
It is then obvious that the sensor must be somewhat warmer than the
water, because it is not far from the middle point.
Without precise data it can only been estimated, not calculated.
Example:
Lets assume the distance sensor-water is 3% of the distance sensor-
steam.
Lets assume there is 3% thermal crosstalk between the 100° hot
steam entry and the sensor, which seems reasonable. Then the sensor
will report 2 degrees more than the water temperature.
Please note:
I dont know, if the e-cat works, or if it doesnt work.
I would wish by heart, that it might work.
But I know, wishful thinking does not work in science and technique.
I doubt it works if the resarch is not made much more carefully
than the demonstration setups.
I guess you missed my analysis of this:
http://www.mail-archive.com/[email protected]/msg52527.html
and the analyses of others.
Best regards,
Horace Heffner
http://www.mtaonline.net/~hheffner/
