On Nov 29, 2011, at 10:38 AM, Jed Rothwell wrote:
This has been discussed elsewhere, but a lot is happening and the
threads here are tangled up with [Vo]:Re:[Vo] problem, so I thought
I would reiterated it. Piantelli has been making some amazing
claims lately. See:
http://ecatnews.com/?p=581
Original source in Italian:
http://www.energeticambiente.it/sistemi-idrogeno-nikel/14742857-
novita-cella-piantelli.html
Some quotes:
[snip]
* Confirms the presence of 6-7 Mev Protons
. . .
END QUOTES
The presence of 6-7 MeV protons can be explained using a deflated
proton reaction with Ni nucleus scenario involving only the release
of zero point energy. I have often wondered why such ZPE-only
reactions have not shown up. I expected this kind of energy release
mechanism to show up in one form or anther, but nothing so blatantly
obvious, given the data, was expected. For background on that (not
very important to understanding what follows) see:
http://mtaonline.net/~hheffner/NuclearZPEtapping.pdf
especially the section "ESTIMATING NUCLEAR HEAT"
The deflation fusion related process being proposed here is this:
1. A lattice environment is created in which the deflated hydrogen
state is frequent for the absorbed hydrogen. Such hydrogen is very
small and has a magnetic moment orders of magnitude larger than a
proton.
2. A Ni orbital electron enters a Ni nucleus and momentarily becomes
magnetically entangled with nuclear components, thus delaying it in
the nucleus and providing the nucleus with a magnetic moment orders
of magnitude larger than typical heavy nuclei.
3. The momentary but strong magnetic binding of both involved
electrons to their respective nuclei, plus the large potential energy
presented by the resulting large magnetic gradient, permits the
tunneling of the neutral deflated state hydrogen into the Ni
nucleus. This is the normal step prior to deflation fusion.
4. Before a strong reaction occurs, the electron of the deflated
proton is stripped and moves off, or tunnels off, into the body of
the Ni Nucleus, possibly momentarily binding with other Ni nuclear
components. This kind of even might be expected to occur on or near
the Ni nucleus surface, possibly in the course of a rebound of the
proton from the nucleus.
5. This leaves the unbound proton in or near the Ni nucleus, the
charge of which is reduced by the 2 electron charges .
6. The unbound proton is repelled away from the nucleus.
7. The first electron, originally bound tot he Ni nucleus, has the
kinetic plus potential energy to escape, once its highly unstable
magnetic binding is broken. The remaining electron momentarily
energetically trapped in the nucleus can either (1) engage in a weak
reaction with up quarks or strange quarks there, or (2) escape via
wavefunction expansion driven by zero point energy or nuclear heat,
the source of which is also zero point energy. In the latter case,
all the kinetic energy applied to the proton has come from the zero
point sea. Both electrons can radiate while in the nucleus,
producing low energy gammas. This extracts nuclear (kinetic) heat,
which essentially is an extraction of energy originally supplied by
the zero point field, and which is continually replaced by the zero
point field.
Ni has atomic number 28, thus 28 protons. With a deficit of 2
charges due to the nuclear electrons, the Ni nucleus has a momentary
charge of 26. 6-7 MeV. This means the mean radius of such protons
from the nuclear center of charge when freed from their principally
magnetically bound electron must be given by Coulomb's law as:
U = 6 MeV = k q (Z-2) / r = (5.6096x10^28 eV m/coul^2) * q *
(28-2) * q / r
r = (5.6096x10^28 eV m/coul^2) * 26 * q^2 / (6 MeV)
r = 6.24 x 10^-15 m = 6.24 fermi
The nuclear radius R_58Ni of 58Ni is:
R_58Ni = (1.2x10^15 m)*(58)^(1/3) = 4.65x10^-15 m = 4.65 fermi
This means the typical proton escape from its magnetically bound
electron occurs within a distance of 1.59 fermi of the 58Ni surface,
about 34% of the Ni nucleus radius away from its surface. The
electron can readily tunnel this distance to the nucleus.
No nuclear transmutation is involved at all.
Further background on the energy of deflation fusion mechanisms can
be found here:
http://www.mtaonline.net/~hheffner/CFnuclearReactions.pdf
especially on pp 2-11.
Best regards,
Horace Heffner
http://www.mtaonline.net/~hheffner/
