At 04:00 AM 12/17/2011, Mark Iverson-ZeroPoint wrote:
I'll get to Robin's two questions at the end, but first this important
clue...
The following is peer-reviewed proof (published in Science and Nature
Photonics) that a high energy photon can be converted to a lower energy
photon with the 'missing' energy coupled into the lattice (physical
vibration)...
Uh, "higher energy." These are laser-generated photons, not gamma rays!
Here is a review of the articles:
http://www.physorg.com/news/2011-12-vibration-entangled-diamonds.html
================== excerpt ========================
The researchers, from Oxford University, National University of Singapore,
and National Research Council of Canada, also sought to exploit another
property of diamond: it tends to scatter light in such a way that a photon
striking it can be converted to a lower energy photon, with the remaining
energy being converted into a vibration. This vibration or 'ringing' in the
diamond crystal can be detected using a laser.
'We sent bursts of laser light through both diamonds,' Ian tells me. 'Most
of the time the light would travel straight through the crystals but
sometimes the light would dump some energy in one of the crystals, setting
it ringing, and the light would then emerge with less energy - a lower
frequency.'
Notice: "most of the time the light would travel straight through the
crystals."
The way I read this is EXACTLY what I proposed a week ago... that the gammas
(or other high-energy photons) which the mainstream has been using to say
LENR is bogus, ARE generated, but they deposit their energy a little at a
time as they are moving through the Pd/D or NI/H lattice.
Okay, but.
Gammas will lose energy travelling through the lattice, it will end
up as heat. There is a serious problem here, being glossed over by
enthusiasm. Gammas of a certain energy will mostly penetrate the
palladium lattice, and this has, I'd bet, been studied. The NAE is
almost certainly on or very near the surface, from where helium is
found. The gammas will mostly escape, unless they head inward, which
perhaps half of them would. Imagining how *all* of the gammas would
be absorbed is what's quite a stretch here. If the main reaction
generates gammas, they would be copious. Instead, if there are any,
they are difficult to detect and establish.
The UNUSUAL
conditions which are present inside the metal lattice form areas which act
like an energy 'SINK', draining the gammas until they cease to exist because
they've deposited all their energy into the lattice. If they do make it to
the outer edge of the Pd or Ni, they might appear as photons, but as much
lower energy photons.
This is quite unlikely. Half the gammas would be oriented outward,
presumably. If something about the NAE orients the gammas inward
(maybe!), then there would be higher absorption. We might be looking
for 24 MeV gammas. That would penetrate a lot of palladium, my guess.
Anyone know the numbers?
Have any CF'ers ever looked for much lower E photons?
I found a shortage of evidence on this. One might think there would
be visible light, at least, but I've seen no record of detection of
light coming from a CF cathode. EUV is quite possible, and we have
discussed how one might look for EUV emissions. It's not simple. EUV
is suspected, I think, from the excited Be-8 nucleus before it
fissions, in Takahashi's theory. The fission dumps about 100 KeV into
two He-4 nuclei, but electrons would be included in the energy
distribution, four of them.
This isn't gamma emission. And if the phenomenon described in the
paper were happening, most of the gammas would still escape, and if
only a small percentage escaped, they'd be detected, lots of people
have looked for gammas.
