Ah, I got double-whammied:

1) It was Beaudette that said "100,000 watts per cm^3" (that string is
outside of the quotation marks meant to designated Preparata's words.

2) Lynn said "gram" rather than "cm^3" so his correction on comma vs period
didn't register with me.

Thanks for clearing that up.

Perhaps Beaudette corrected that in his 2002 edition.  I was reading from
the 2000 edition.

In any event, the high *reproducibility* of Preparata's work has not yet
been equaled has it?

On Thu, Jan 12, 2012 at 1:21 PM, Jed Rothwell <[email protected]> wrote:

> James Bowery <[email protected]> wrote:
>
> ([1E9 * ounce_troy] * [{12.02 * gramm} / {(centi*meter)^3}]^-1) * ([100 *
>> {kilo watt}] / [{centi*meter}^3]) ? watt
>>
>> = 2.5876415E14 W
>>
>> over 200 terawatts.
>>
>
> Unfortunately, I think Preparata meant "100" not 100,000. The comma is a
> decimal point. I do not understand why he added 3 digits of precision to a
> rough approximation. Anyway, that comes to 0.2 TW, which is about 1/100 of
> world energy production. Fleischmann once estimated that Pd can supply
> about 1/3 of total energy. I confirmed it is in that ballpark, ~30% to ~50%.
>
> Here is my estimation.
>
> I assume that power density and temperature with palladium can be
> increased to the limits of the material. That is to say up to the highest
> temperatures in which  thin-film palladium can survive. Or nanoparticles in
> aerogel, or what-have-you. The limiting factor is how thinly you can spread
> the palladium and have it remain on the substrate and in contact with the
> medium, which will probably be D2 gas.
>
> About half of palladium nowadays is used in catalytic converters. Hot gas
> from internal combustion engines flows over the palladium surface and is
> catalyzed. I assume this technology is pushed to the limit. They use the
> smallest amount palladium they can, spreading it as thinly as they can with
> maximum exposure to the moving gas. A palladium based cold fusion cell
> would have palladium spread roughly as thin as this, producing temperatures
> roughly as high as this. If they could make in any thinner, they would.
> This technology has been around for a while and it is probably mature.
>
> Nearly all of the energy from an automobile is wasted as hot gas. In other
> words, the hot gas that passes over the palladium surface is roughly equal
> to the total amount of energy produced by gasoline in the transportation
> sector. To put it another way, if the heat was being produced by the
> palladium inside the catalytic converter, instead of coming from the engine
> to the converter, you would get nearly as much energy as you get from
> gasoline now.
>
> To simplify a great deal, assuming that cold fusion can achieve the same
> temperatures as palladium experiences in a catalytic converter, half of our
> palladium could produce roughly as much energy as the entire automotive
> transportation sector does now: 27 out of 99 quads. All of our palladium
> could therefore produce roughly 50 out of 99 quads.
>
> Actually the number is higher for various reasons:
>
> * The palladium is not used up as quickly in a cold fusion device as it is
> in a catalytic converter.
>
> * The palladium is more easily and completely recovered from a used cold
> fusion cell, assuming it is not transmuted.
>
> * Palladium production will be increased as demand increases.
>
> This is a crude estimate but I believe it does show that there is not
> enough palladium to produce all the energy we need. If it turns out
> palladium is the only suitable metal, we would have large centralized
> generators producing most of our energy, supplying it as electricity for
> use in electric cars and so on. We would not actually put the palladium in
> automobiles, and probably not in houses either.
>
> - Jed
>
>

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