Speed increases as the satellite orbits closer to its parent, and slows as the 
orbit is extended.  As the x-axis is a linear representation of time, the 
changes in speed during orbit serve to "compress" the wave troughs and expand 
the wave peaks.  Thus the wave resembles more of a bouncing ball than a simple 
sine.
 


> Date: Thu, 1 Mar 2012 11:25:02 -0500
> Subject: Re: [Vo]:Nature Editorial: If you want reproducible science, the 
> software needs to be open source
> From: [email protected]
> To: [email protected]
> 
> On Wed, Feb 29, 2012 at 12:50 PM, OrionWorks - Steven V Johnson
> <[email protected]> wrote:
> > From Harry:
> >
> >>> From OrionWorks:
> >>> What I can say is that the new system involves an alternative way of 
> >>> graphing out a periodic orbit - where you plot an "elliptical" orbit on a 
> >>> TIME-LINE chart. The orbital distance is the "Y" vertical value and the 
> >>> horizontal "X" value is the time value.
> >>
> >> That graph should look something like a sine curve....or not?
> >
> > You're on the right track. However the time-line looks more like a
> > bouncing ball.
> 
> I think I understand now. You are mapping a two dimensional distance
> vector to the distance axis of your distance-time graph, so that a
> perfectly circular orbit corresponds to a straight line.
> This differs from a distance time graph in an introductory course in
> physics where the distance axis represents the length of a one
> dimensional vector so that a straight line in this graph corresponds
> with a stationary body (and by implication zero velocity and zero
> acceleration.)
> 
> 
> 
> 
> > The "bouncing" part is where the satellite has reached the perihelion
> > (closest distance) in the orbital period.
> 
> I am puzzled by this. Why isn't there a "bouncing part" at the aphelion?
> 
> > Ironically, at this moment
> > in time I would conjecture that it would not be incorrect to stipulate
> > that the orbiting satellite is behaving as if it's being influenced by
> > a NEGATIVE gravitational field. That's where the 1/r^3 (cubed) part of
> > the algorithm comes into play. It influences the direction the
> > satellite is taking by pushing it away. Traditionally speaking, we are
> > used to interpreting that aspect of the orbit as the influence of
> > centripetal action. It's all a matter of interpretation! The cubed
> > (negative forces) influence only comes into play in close proximity to
> > the planet for which the satellite is orbiting around. At farther
> > distances, the normal 1/r^2 (attractive forces) take over.
> >
> > It's really kind of a nifty perspective, if not a little wacky! ;-)
> >
> > Regards
> > Steven Vincent Johnson
> > www.OrionWorks.com
> > www.zazzle.com/orionworks
> >
> 
                                          

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