Eric,
I’m not suggesting this relates to Rossi or Defkalion at all. I’ve seen no suggestion that either of them uses lithium. According to the Authors, they believed it could explain some of what was going on in the early nineties in LENR with lithium hydroxide electrolytes. Many, if not all, of those experiments were with heavy water – yet the explanation applies to electrons – go figure. However, the DDL explanation could relate to why we continue to see problems with lithium batteries – especially failure following overcharging. It would not take many of these Li-H -> 2He reactions to destroy a battery. I have seen estimates that as many as one billion lithium batteries have been recalled since they started appearing in laptops, resulting in huge losses for a few, mostly Japanese companies, including big names like Sony. There has been a concerted effort to hide the immensity of the problem. If you are wondering why A123 is tanking – it could related in some degree to this very subject. http://www.autoblog.com/2012/04/12/five-people-hurt-in-gm-lab-explosion-a123-battery-reportedly-re/ If one accelerates helium nuclei in a beam line to 8-9 MeV so as to impinge on a target, you will see a massive amount of radiation; which of course is not seen in any LENR experiment where lithium has been part of the electrolyte. Personally, I think that the DDL/lithium fusion explanation does not apply to deuterium at all, since there would be some neutrons expected, but DDL electron decay could apply – in which no helium will be seen. However, most of us are not longer interested in heavy water reactions, since it appears that they are not necessary, and the cost and regulations are problematic. In the case of “DDL and f/H” as opposed to DDL and deuterium, the expected yield from fusion/fission itself could be much less than the known reaction (since the f/H is energy depleted already). Plus, the energy release could be spread out in time via EUV emission, or both. In fact the beauty of this route for Li-H, would be that the beryllium intermediary product could release a lot of the energy before the double alpha decay – that is to be expected. However, except for the continuing problems of lithium battery failure, there is not much hard evidence to go on. Jones From: Eric Walker Think about the ideal fusion reaction. IMHO the best candidate on paper is Li-H, where lithium of mass 7 reacts with a proton to produce unstable beryllium 8, which splits very quickly into two very hot alpha-particles (helium). Are you thinking that the lithium comes from the electrolyte? Perhaps that would explain why a surface reaction seems to be involved in the case of electrolyte systems. What about when potassium is used? Where does the lithium come from in the case of a gas phase system? This Li-H reaction, has been called "fusion/fission" since it is a bit of both, but the net gain is equivalent to about 17 MeV divided equally between the alphas - which is about 20 million times greater than combustion, pound for pound. 8.5 MeV per alpha is a lot of energy. What secondary emissions would you expect to see when the alphas collide with things in the environment? Eric
