In reply to Jones Beene's message of Mon, 25 Jun 2012 10:27:35 -0700: Hi, [snip] >There are two additional possibilities, in addition to the energy depleted >f/H ... which could explain two alphas which are in far lower in energy and >do not produce spallation effects. One is the strong force depletion >mentioned above and the other is the release of neutrinos, as well as two >alphas.
The reaction H + Li7 => 2*He4 + 17.35 MeV is based purely on the difference in mass, it has nothing to do with hot fusion, and is in fact completely independent of the method employed. The initial H is indeed depleted, by about 360 keV, which reduces the total to about 17 MeV, or 8.5 MeV per alpha. Still sufficient to produce the occasional spallation neutron. As to "Plus we must assume that the reaction also depletes the strong force in a way that reduces the mass of the end products." ...I fail to see why we must make any such assumption. BTW there are no neutrinos involved in this reaction at all, because it's not a beta decay reaction. It's a straight fast fusion/fission reaction. (The total number of protons & neutrons is the same before as after.) Regards, Robin van Spaandonk http://rvanspaa.freehostia.com/project.html
