Find here some simple calorimetry calculations : Electrical energy given to the system : 4.33 hours @ 12 watt = 187056 J => 44677 cal To rise the temp from 55 F to 146 F, the system need 50 cal/g of water. (Assuming electrodes and recipient are negligible) Assuming no loss of heat by dissipation, the electrical energy released will rise the temperature of 44677 / 50 = 884g of water. If Jack use more than 884g of water, we are sure that there is another energy source (chemical or other).
_____ From: ken deboer [mailto:[email protected]] Sent: lundi 1 octobre 2012 19:00 To: [email protected] Subject: Re: [Vo]:Replication of Chuck Sites Nickel/Boron Experiment Very interesting, indeed. How much water are you using? If everything were 100% efficient, and you were inputting 12 watts/hr = ~40 btu/hr, over 3 hours you would have 120 btu, which theoretically could raise 1 pound of water 120 F. Best regards, kend On Mon, Oct 1, 2012 at 10:38 AM, Jack Cole <[email protected]> wrote: Thanks Jed, glad to do it. Small update: 7 am Temp 55F Start 9 am Temp 110F 10 am Temp 129F 11:20 am Temp 146F Outside temp started at 55F and was at 57F at 11:20 am. I'll keep running until the temp levels off. At that point, I'll work on setting up a control cell. The water has turned brown, so I presume something is also happening with the copper (either in the nickels or the exposed portion of copper wire attaching to the electrode). On Mon, Oct 1, 2012 at 10:00 AM, Jed Rothwell <[email protected]> wrote: Thanks for doing this! - Jed
