Quick arithmetic: 1m^2*.033W/(m*deltaK)*2deltaK/2in?W <http://www.testardi.com/rich/calchemy2/> ([{(1 * [meter^2]) * (0.033 * watt)} / {meter * deltaK}] * [2 * deltaK]) / (2 * inch) ? watt = 1.2992126 W
That's for styrofoam 2 inches thick and a cooler with total surface area of 1m^2 and a 2 degree Kelvin temperature difference with ambient. On Wed, Mar 6, 2013 at 2:23 PM, James Bowery <jabow...@gmail.com> wrote: > Hmm.... perhaps but one would think that if the water containers were > covered Styrofoam coolers, the temperature differences might accumulate > sufficiently to render the signal -- particularly given the distribution > represented by the numerous control containers -- quite significant. > > Admittedly, I haven't done the arithmetic. > > > On Wed, Mar 6, 2013 at 2:18 PM, Jed Rothwell <jedrothw...@gmail.com>wrote: > >> James Bowery <jabow...@gmail.com> wrote: >> >>> >>> A properly designed Seebeck is a lot more than that. >>>> >>>> >>> With an infinite COP all that's necessary is a room with a bunch of >>> similar pots of water, one of which has the infinite COP device in it. >>> >> >> With only one watt I do not think that would work well. Background >> changes in temperature would swamp the effect of the 1 W heat source. That >> was the problem with the open-air Arata demonstration and others like it I >> have seen. >> >> I am not saying it wouldn't work at all, but the data would be noisy and >> people would wonder if it wasn't the effect of the HVAC currents of air >> blowing on one dish and not the other, or what-have-you. >> >> With ~10 W in a small device your method would work. >> >> - Jed >> >> >
