If you noticed, the isotopes of nickel Ni58, Ni60, Ni62 will produce a radioactive isotope of copper that will decay back to the original Nickel isotope.
However, the Ni64 isotope will produce an isotope of Zinc, 39% of the time. Quite remarkably, this sets up an infinite loop of radioactive isotope production where positions are generated. The copper is almost the same thing in the production of radioactive zinc. But nickel is always the final stable product in the isotope loop. This could be the reason why nickel is a great LENR substrate. On Mon, Apr 22, 2013 at 6:03 PM, <[email protected]> wrote: > In reply to Axil Axil's message of Mon, 22 Apr 2013 12:02:01 -0400: > Hi, > [snip] > >The W- boson then converts the neutron into a proton which converts the > >atom from one element to another. > > Such a conversion only results in an energy release if the initial isotope > is > radioactive to beta decay, and in that case, no LENR is required, it will > decay > of it's own accord given enough time. > > Regards, > > Robin van Spaandonk > > http://rvanspaa.freehostia.com/project.html > >
