However, the Ni64 isotope will produce an isotope of Zinc, 39% of the time.
should read However, the Cu64 isotope will produce an isotope of Zinc, 39% of the time. The speculative ground rule for LENR is that electric charge concentration will destabilize a stable element by converting a neutron to a proton in the Ni nucleus: Ni62 goes to Cu62. On Mon, Apr 22, 2013 at 6:19 PM, Axil Axil <[email protected]> wrote: > If you noticed, the isotopes of nickel > Ni58, Ni60, Ni62 > > will produce a radioactive isotope of copper that will decay back to the > original Nickel isotope. > > However, the Ni64 isotope will produce an isotope of Zinc, 39% of the time. > > Quite remarkably, this sets up an infinite loop of radioactive isotope > production where positions are generated. > > The copper is almost the same thing in the production of radioactive zinc. > But nickel is always the final stable product in the isotope loop. > > This could be the reason why nickel is a great LENR substrate. > > > > > > > On Mon, Apr 22, 2013 at 6:03 PM, <[email protected]> wrote: > >> In reply to Axil Axil's message of Mon, 22 Apr 2013 12:02:01 -0400: >> Hi, >> [snip] >> >The W- boson then converts the neutron into a proton which converts the >> >atom from one element to another. >> >> Such a conversion only results in an energy release if the initial >> isotope is >> radioactive to beta decay, and in that case, no LENR is required, it will >> decay >> of it's own accord given enough time. >> >> Regards, >> >> Robin van Spaandonk >> >> http://rvanspaa.freehostia.com/project.html >> >> >
