OK, you are mistaken with this analysis.  The input power is determined by the 
AC 50/60 hertz fundamental and the fundamental component of the current flowing 
from the wall socket.  The DC just comes along for the ride since it is 
converted from some of the input AC power.

And yes, you can measure accurately the input power with a good instrument that 
does not measure the DC component.  I can explain further if you like.

Dave


-----Original Message-----
From: Duncan Cumming <[email protected]>
To: vortex-l <[email protected]>
Sent: Mon, May 27, 2013 2:11 pm
Subject: Re: [Vo]:Re: [Vo]:Re: [Vo]:Re: [Vo]:Torbjörn Hartman describes power 
measurments


          
    
What I am proposing is a lot simpler      than that. No bridge rectifier, no 
capacitor, just a simple diode.      I am saying that given a diode in series 
with a resistor, it is      not possible to measure the power using a clamp on 
ammeter.
      
      I am not suggesting that anybody has performed a scam. I am      
suggesting that the equipment used would not have measured the      power 
consumed by the resistor if rectification were present in      the controller 
box.
      
      Is there anybody reading this that can do SPICE simulations? Might      
it be possible to simulate a resistor in series with a diode and      determine 
the actual and apparent power if an AC coupled current      meter is used?
      
      Duncan
      
      P.S. I never mentioned either bridge rectifiers or capacitors. In      
the case of a bridge rectifier type power supply, then a clamp on      ammeter 
will work OK. I do not suspect such a thing in the demo.
      
      On 5/26/2013 7:35 PM, David Roberson wrote:
    
    
        
Assume that you have a bridge            rectifier in the blue box.  This is 
followed by a filtering            capacitor.  The DC is then used by the 
electronics connected            to the capacitor.  Are you saying that it is 
not possible to            determine the power input to this type of network by 
           measuring the input AC voltage and current?  Or are you            
saying that someone has performed a scam and put a DC supply            in 
series with the normal AC voltage?
        
 
        
You do know that this could easily be measured by a simple          DC 
voltmeter, right?
        
 
        
Dave
        
-----Original Message-----
          From: Duncan Cumming <[email protected]>
          To: vortex-l <[email protected]>
          Sent: Sun, May 26, 2013 10:01 pm
          Subject: Re: [Vo]:Re: [Vo]:Re: [Vo]:Re: [Vo]:Torbjörn Hartman         
 describes power measurments
          
          
            
              
Almost. The power being fed                to the heater exceeds that measured 
at the wall, because                the sensor used (an AC current clamp) 
cannot sense the                direct current being drawn from the wall socket.
                
                Some people find the difference between current and             
   voltage confusing. What I am saying here is that if you                
connect a resistor in series with a diode to a wall                socket, then 
the CURRENT drawn is direct even though the                VOLTAGE at the 
socket is alternating. (Rossi does not                seem to understand this 
concept judging by his message                that got posted today). So unless 
you use a DC rated                current meter (such as a shunt) you will not 
sense all                of the current, and hence power, drawn from the wall   
             socket. 
                
                The electrical power meter in your house certainloy IS          
      rated for DC, so you will certainly be BILLED for the                
power even though you didn't measure it yourself!
                
                V = IR
                Power = Voltage * Current * Power Factor
                
                Duncan
                
                On 5/26/2013 5:57 PM, Eric Walker wrote:
              
              
                
I wrote:
                  
                    

                      
                        
On Sun, May 26, 2013 at 5:18 PM,                          Duncan Cumming 
<[email protected]>                          wrote:                       
   
 
                            
                              
                                
                                  
                                    
I am not trying to assert                                      anything as 
fact. I am merely                                      pointing out that a 
simple diode                                      inside the controller box (to 
                                     which access was forbidden by              
                        Rossi) COULD HAVE given the                             
         observed results. I am NOT saying                                      
that it, in fact, did, merely                                      speculating 
that it could have.
                                    
                                  
                                
                              
                              
                            
                          
                          
Am I right in                            understanding that this line of 
reasoning                            requires tampering with the mains itself,  
                          where the electrical measurements were made,          
                  in addition to any sly customizations that                    
        might have been made at the controller?
                        
                      
                    
                    
                  
                  
I think I'm starting to                    understand.  This is a separate line 
of reasoning to                    the one about the possibility of hidden DC 
and RF                    passing undetected through the clamp meters at the    
                mains.  In this line of reasoning, the duty cycle               
     (35 percent ON) is misunderstood, and there is a                    hidden 
DC component from the controller delivering                    power to the 
E-Cat, but not above what was read from                    the wall -- am I 
describing this right?
                  

                  
                  
Eric
                  

                  
                
              
              
            
          
        
          
    
  

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