I think Pekka is right. If the camera samples above the peak wavelength,
and it is a grey body, then an emissivity of 1 seems to be always
conservative.

I'm still not entirely sure how the effective exponent works in the
instrument software, but I did a calculation similar to Pekka's, if a
little simpler: For a given temperature, I found the value of the Planck
curve at the camera sensitivity (say 10 µm). Then I found the temperature
needed to give the same value from a Planck curve scaled by an emissivity.
Finally, I calculated the power using the new temperature and the same
emissivity.

The temperature is always higher for a lower emissivity as expected. The
effect of the emissivity compensates somewhat in the power calculation, but
like Pekka, I also found the net effect is positive in all the cases I
tried. It's obvious from the curve that the temperature should be higher,
but it's not obvious to me that the reduced power from smaller emissivity
would never compensate, but that appears to be the case if the peak
wavelength is shorter than the sampling wavelength, which is the case in
these experiments. I also tried the calculation for much lower values of
emissivity, and the calculated power was higher in every case.

As I said, the actual effect for all emissivities could be determined with
a bit of effort, and the results do favor the authors. But it's not as
simple as arguing the calculated temperature is higher if the emissivity is
lower as some (including the authors) did, nor as simple as arguing the
calculated power is lower because of lower emissivity, as others did. The
two effects compete, and it's the net effect that's important.

So, the only way the camera could give an overestimate of the power is if
the emissivity has some kind of strong wavelength dependence, and I rather
doubt a material exists that would give a factor of 3 or more error.

So, the upshot is that I can't explain the power gain with an error in
emissivity in either experiment. I conceded as much for the March
experiment from the beginning, where they measured the emissivity, and that
is presumably the more significant run anyway. Even so, I would not be
satisfied with this kind of indirect and complex route to a power
calculation when flow calorimetry would be far more direct and accurate,
even if experimentally more difficult. Still, you can buy tube furnaces
with the insulation and cooling lines already set up, and it would not be
difficult to adapt such a thing for Rossi's purposes. A big advantage of
flow calorimetry is that you can integrate the heat in a very visual kind
of way, by collecting, or even circulating the cooling water, thereby
raising the temperature of a known volume of water in a 1000 L tub, say.

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