At this level, it should be possible to power a steam electric generator to provide the inputs.
On Mon, Jul 29, 2013 at 3:48 PM, David Roberson <[email protected]> wrote: > They(DGT) intentionally left out the vaporization as a "gift to the > skeptics" according to what was stated. There is evidence that the water > was vaporized into steam which was then superheated to dry vapor. I > calculated over 20 kilowatts was being delivered. > > Dave > > > > -----Original Message----- > From: Jed Rothwell <[email protected]> > To: vortex-l <[email protected]> > Sent: Mon, Jul 29, 2013 4:01 pm > Subject: [Vo]:Defkalion apparently ignored heat of vaporization > > I am looking at the Josephson version of the Defkalion video, here: > > http://www.youtube.com/watch?v=HHEtnTO3h6s > > It is a little more blurry than the original. At time 39:03 the numbers > on the screen can be read. Total input is 1918 W. Output is 4295 W. T_in is > 25.29°C, T_out 132.13°C, and the flow rate is 0.569 liters/min. > > 132.13°C - 25.29°C = 106.9°C > > 0.569 liters/min = 9.5 ml/s > > 106.9°C * 9.5 ml = 1014 calories > > 1014 cal * 4.2 = 4258 W > > That is approximately what is shown in the Output Power section of the > screen. > > I have heard that the device produced steam. This is shown at various > times in the whole video. From the numbers here, I conclude that the people > at Defkalion treated the output as hot water, ignoring the heat of > vaporization. The heat of vaporization of water is 2260 kJ/kg, or 2260 J/g, > so for 9.5 ml that would be an extra 21,470 J/s (watts). > > I gather there have been some disputes over whether this water was fully > vaporized. It might have been somewhat wet. It might have included unboiled > water. I don't see how it could have, at 132°C, but in any case that is > irrelevant since they ignored the heat of vaporization. > > This is very conservative estimate of the heat output. > > - Jed > >
