In order to make a convenient commercial product, a hydride compound that sublimates (releases hydrogen) when the temperature of the reactor is increased is required. This hydrogen production mechanism need not be located in the mouse.
I believe that the job of the mouse is to produce nano-particles as a product of heat it produces beyond the melting point of an alkali metal (most probably potassium). The nuclear active sites that these nanoparticles produce through amalgamation will degrade over time due to nuclear activity and must periodically be rebuilt by a reapplication of high temperature heat. When the temperature of the E-Cat gets above a set temperature, other high temperature nano-particle processes take over and control is lost. By the way adding to the list of candidates, lithium hydride is another candidate that will produce uncontrolled high temperature nanoparticle reactions. Normally, there is little oxygen present in the Rossi reactor because oxygen will produce uncontrollable and chaotic LENR activity inside of the nuclear active sites. On Sun, Dec 29, 2013 at 2:26 PM, Eric Walker <[email protected]> wrote: > On Sun, Dec 29, 2013 at 10:13 AM, Daniel Rocha <[email protected]>wrote: > > The "mouse" is nothing more than a ceramic canister within his SS tube >> full of (most probably) MgH and Ni acting as a catalyst to brake the >> released H2 to atomic from its solid state MgH at high temperatures. If H >> or Mg are in contact with air or moister then a Lungmuir toarch reaction >> (reaching 3400C) and/or a violent reaction of Mg with H20 give such >> "explosing" results lasting for some seconds. Such are not desirable >> results but accidents due to poor controllability. >> > > Interesting idea. You say this with some confidence -- can you elaborate > on the basis of this confidence? > > If the "mouse" is a ceramic canister with MgH (or something comparable), I > think the implication is that it is Rossi's Hot Cat, specifically, that is > prone to meltdowns, and not the underlying LENR itself? Why is it > necessary to break down H2 into monoatomic H if the H is going to recombine > right away once it migrates away from the ceramic canister, presumably well > before it gets to the Ni? If some Ni is in the "mouse," what is in the > "cat"? > > What is a Langmuir torch reaction? Is this rapid hydrogen recombination? > > Eric > >
