Bob,

You ask an excellent question and I would also like to understand the answer.  
We assume that linear momentum does not have quantum values so that it can 
exist in smooth continuous states.  Has this been proven?  Perhaps someone can 
analyze the HUP and show how it is so.

Also, your question leaves me wondering why the angular spin must be quantized 
instead of continuous.  If I recall, some of the quantized states are a result 
of explaining the incremental energy levels that electrons find themselves 
exhibiting while orbiting nuclei.  Perhaps this determination is based upon 
measurements instead of forced by firm laws of physics.  This may be an example 
of empirical leading theoretical.

After all, in classical macro systems the total angular momentum can be 
constructed by breaking the mass into tiny increments and summing their linear 
momentums.  The differential elements on opposite sides of the material balance 
out in magnitude but are not operating along the same geometric lines.  Each 
tiny component appears to have continuous values of linear momentum instead of 
quantized states.

I suppose that spin might not translate into the same phenomena as true macro 
angular momentum.  Perhaps someone can help with this issue.

Dave

 

 

 

-----Original Message-----
From: Bob Cook <[email protected]>
To: vortex-l <[email protected]>
Sent: Sat, Jul 12, 2014 3:25 pm
Subject: Re: [Vo]:Dynamic nuclear polarization



Dave--


I understand the frame of reference idea.  However what is the mechanism that 
controls the fractionation of linear momentum among the particles.  In angular 
momentum the intrinsic quantum controlled parameter of spin exists.  The is no 
intrinsic quantity of linear momentum that is balanced in the kinetic energy of 
the particles.  I have assumed that some unexplained couple between mass and 
gravity must control linear momentum on a continuous scale, scale rather than 
in quanta as angular momentum is controlled.  


This is the question I raise relative to the decay of radioactive entities.   
How is the momentum of the emitted particle(s) and the residual sometimes large 
particle determined within the small confines of the original decaying particle?


I have often speculated it  is mediated by the addition of a  entity  with 
significant momentum that results in a hot- like nuclear reaction with transfer 
of some momentum to the various fission fragments.    The addition of magnetic 
fields allows the interaction of the incoming entity to interact more often, 
possibly by changing the 3-D structure with its interaction probability to a 
2-D situation with higher probability of interaction.


Bob



Sent from Windows Mail



From: David Roberson
Sent: ‎Saturday‎, ‎July‎ ‎12‎, ‎2014 ‎9‎:‎22‎ ‎AM
To: [email protected]



Bob,

A careful choice of your reference frame can help resolve many of the linear 
momentum issues.  I like to choose one that is located at a point where the net 
linear momentum of the particles is zero before the reaction.  Under that 
condition it is relatively easy to follow the reactions since the final 
momentum must also remain zero and avoids nasty math errors.

Dave

 

 

 

-----Original Message-----
From: Bob Cook <[email protected]>
To: vortex-l <[email protected]>
Sent: Sat, Jul 12, 2014 3:50 am
Subject: Re: [Vo]:Dynamic nuclear polarization



Dave--


I would assume in the hot fusion regime that significant linear momentum must 
be conserved in addition to the conservation of energy associated with kinetic 
energy of colliding particles.  In cold fusion LENR there is know momentum 
other than angular momentum to conserve.  Gammas   and other linear momentum 
carrying particles are not needed and in fact not possible because of their of 
their necessary of carrying linear momentum.   it  is for this basic reason 
that I do not anticipate the existence of ganmas or  any energetic particle to 
be associated with LENR. 


If any has a good physical explanation of the mechanism for the distribution of 
the linear momentum between decay products I would love to see it.


Bob 









Sent from Windows Mail



From: David Roberson
Sent: ‎Friday‎, ‎July‎ ‎11‎, ‎2014 ‎11‎:‎31‎ ‎AM
To: [email protected]



When I take a step back I realize that it appears like a miracle for the energy 
to always come out in small fractions of the total available.  I have to ask 
whether or not this unusual situation may be related to the conditions upon 
which the reaction occurs.  Is anyone aware of an experiment that actually 
involves fusion of D x D at low temperatures while the radiation is monitored?  
 We do have data describing what is released at very high kinetic energies, but 
is there a threshold below which our preferred path may be exclusive?

I suppose the closest analogy would be muon fusion.  If I recall, that pretty 
much matches what is emitted under hot fusion conditions.  Perhaps your point 
is valid and there is zero chance that D x D fusion is taking place directly.  
If true, some sneak path is being followed and it is common for alpha radiation 
to be generated in nuclear reactions.

Plenty of energy can be deposited by alpha radiation into the structure.  
Keeping that under control without generating gammas is quite a trick.  And, 
what other nuclear ash should we be seeing?

I hope that Rossi and the future report from the long term experiment will help 
to answer many of our questions.

Dave

 

 

 

-----Original Message-----
From: Jones Beene <[email protected]>
To: vortex-l <[email protected]>
Sent: Fri, Jul 11, 2014 2:19 pm
Subject: RE: [Vo]:Dynamic nuclear polarization




From:David Roberson 
 

I think Bob is hoping that energy can be taken away in smallerchunks and that 
is what I would want to see as well….Hasanyone identified exactly where the 
large MeV energy from a D x D fusion isstored?  It remains in place for a short 
duration until released. Perhaps it can be taken in many portions instead of 
one dangerous gamma.  
 
Dave,
 
Once again, the relevantquestion is not whether energy can be released 
piecemeal, in many smallundetectable portions. We can assume that it can.
 
The relevant question is this:can a new and previously unknown mechanism 
accomplish this incredible feat 100%of the time, to the complete exclusion of 
the known mechanism?
 
Clearly – that is most unlikely.
 
The 23 MeV would need tocome out in packets of no more than about 6 keV each. 
Anything above this levelwould show up on the kind of meters which have been 
used for many years, andwhich have already proved that strong radiation above 
background level is seldomseen.
 
Think about it. That lackof any radiation signature in most experiments of this 
kind means the large amountof energy (from the formative alpha particle) comes 
out in at least 4,000 individualpackets, none of which can ever be larger than 
what is detectable. And furthermore,never ever do we see the “known release 
mechanism” of standard physics. If true,this proposition is moving towards an 
“intelligent” release of radiation, inwhich packets must be monitored and 
rejected if they are too energetic. 
 
That kind of control isabsurd, of course, but it highlights the larger 
absurdity of suggesting thatthis reaction must involve the fusion of deuterons 
to helium with no gammasignature. There are better alternatives.
 
Jones
 
 







Reply via email to