Terry--
Bound in Hydrogen is a little different question. I assume you mean a free
neutral hydrogen atom, not a negative hydrogen ion or hydrogen molecule or
deuterium or tritium. The answer is yes. I did a long time ago (1956)
based on the Bohr model of hydrogen atom. In fact I also did a measurement
of the lowest energy state, which assumed a rest mass of the electron and
confirmed the Rydberg constant (assuming a refractive index for air) to 8
significant figures. The experiment measuring the hydrogen atom spectrum
lines was not done in a vacuum and thus the reactive index of air was
necessary to consider.
However that calculation did not consider spin energy associated with the
electron. A good spectrometer might have allowed me to see the difference
between an election in the "ground state" with -1/2 spin energy vs one in
a higher state with +1/2 spin. Again what I calculated assumed an average
spin energy of 0. A strong magnetic field would have separated those spin
states in energy and may have allowed me to calculate the lower state from
experimental excited hydrogen spectrum data.
As I recall the mass of the electron in the Bohr model calculation matched
the mass seen calculated from the annihilation experiment to 3 or 4
significant figures.
Bob
----- Original Message -----
From: "Terry Blanton" <hohlr...@gmail.com>
To: <vortex-l@eskimo.com>
Sent: Wednesday, September 17, 2014 5:04 AM
Subject: Re: [Vo]:Rossi on Ni62
On Wed, Sep 17, 2014 at 8:03 AM, Terry Blanton <hohlr...@gmail.com> wrote:
On Wed, Sep 17, 2014 at 12:44 AM, Bob Cook <frobertc...@hotmail.com>
wrote:
Terry--
Your theory is sane. That's my theory too.
Have you successfully calculated the total energy contained in an
electron in ground state?
Oops, bound in hydrogen.
