Can you attach that photo? I am not sure which one On Wednesday, October 15, 2014, Robert Lynn <[email protected]> wrote:
> Additionally, look at the darkened photo, the wire exterior to the reactor > sourrounded by cooler materials to radiate to are brighter than the bright > wires in the reactor. Hard to believe it would be colder inside the > reactor surrounded by relatively hotter materials that are harder to > radiate to. I think that is pretty strong indication that it is the wires > that are the bright areas. > > On 15 October 2014 20:14, Robert Lynn <[email protected] > <javascript:_e(%7B%7D,'cvml','[email protected]');>> wrote: > >> I am looking at high zoom at the same photos and finding it easy to draw >> the opposite conclusion. Confirmation bias on both our parts :) >> I think it is equivocal at best. >> >> On 15 October 2014 19:52, ChemE Stewart <[email protected] >> <javascript:_e(%7B%7D,'cvml','[email protected]');>> wrote: >> >>> If you zoom in very closely on the hot reactor photos you can see the >>> the dark lines are of uniform width, continuity and shade. I am 95% >>> confident that is the shadow of the coil. The light areas change in >>> brightness, width, etc. >>> >>> On Wed, Oct 15, 2014 at 3:56 AM, Robert Lynn < >>> [email protected] >>> <javascript:_e(%7B%7D,'cvml','[email protected]');>> wrote: >>> >>>> how do you know this? How do you know the the wire is not the >>>> brightest area? >>>> >>>> On 15 October 2014 15:06, H Veeder <[email protected] >>>> <javascript:_e(%7B%7D,'cvml','[email protected]');>> wrote: >>>> >>>>> Some people suspect that the resistor wire can't be Inconel because >>>>> they are predicted to melt at the reactor's operating temperature. >>>>> However, >>>>> since we know the resistor wire casts a shadow in the alumina, the >>>>> temperature of the wire remains below the operating temperature and >>>>> therefore can't melt. >>>>> >>>>> Harry >>>>> >>>> >>>> >>> >> >
