" This is the likely what makes it appear that there is a gain above 1. "
So at least we have you now believing that a wire cannot create a gain above 1 and that the wire is not inside the reactor core. I wonder if we can estimate number of coil wraps from the photo(dark bands), we might be able to estimate an inductance On Wednesday, October 15, 2014, Robert Lynn <[email protected]> wrote: > Not if it is touching the walls of inner or outer alumina tube in places, > intermittent contact due to vagaries of original wire winding around inner > tube and subsequent large differential thermal expansion so that the wire > is quenched in some places but not in others. Would explain the variation > in glow that we see (along with slight translucence of alumina tube), and > would change as the wire gets hotter and relaxes pre-existing springiness > that might otherwise hold the wire in contact with the inner tube - would > lead to wire temperature increasing faster than power input would suggest - > ie what we see with supposedly increasing COP. > > Most likely means of construction is winding wires around an inner tube, > or winding them around a different mandrel and then slipping them over the > tube. Bonding them to the inner tube is an extra step that (based on > inconsistency/variability of surface glow) has likely not been done and for > which their would be little initial motive anyway. And massive relative > thermal expansion of the wire (~1%) would likely have cracked any ceramic > bonding or attempts to rigidly encase the wires or bond them to the inner > tube anyway. > > Differential thermal expansion means that the internal tube/vessel is > likely only bonded to the thermocouple end cap, otherwise the external tube > would be broken by axial stress due to differential thermal expansion of > higher temperature of inner tube compared to external tube. > > On 16 October 2014 10:58, H Veeder <[email protected] > <javascript:_e(%7B%7D,'cvml','[email protected]');>> wrote: > >> >> If the wire inside the reactor was hot enough to glow it should produce >> a more uniform spiral glow along the entire length of the tube. >> >> >> Harry >> >> On Wed, Oct 15, 2014 at 8:19 AM, Robert Lynn < >> [email protected] >> <javascript:_e(%7B%7D,'cvml','[email protected]');>> wrote: >> >>> Additionally, look at the darkened photo, the wire exterior to the >>> reactor sourrounded by cooler materials to radiate to are brighter than the >>> bright wires in the reactor. Hard to believe it would be colder inside the >>> reactor surrounded by relatively hotter materials that are harder to >>> radiate to. I think that is pretty strong indication that it is the wires >>> that are the bright areas. >>> >>> On 15 October 2014 20:14, Robert Lynn <[email protected] >>> <javascript:_e(%7B%7D,'cvml','[email protected]');>> wrote: >>> >>>> I am looking at high zoom at the same photos and finding it easy to >>>> draw the opposite conclusion. Confirmation bias on both our parts :) >>>> I think it is equivocal at best. >>>> >>>> On 15 October 2014 19:52, ChemE Stewart <[email protected] >>>> <javascript:_e(%7B%7D,'cvml','[email protected]');>> wrote: >>>> >>>>> If you zoom in very closely on the hot reactor photos you can see the >>>>> the dark lines are of uniform width, continuity and shade. I am 95% >>>>> confident that is the shadow of the coil. The light areas change in >>>>> brightness, width, etc. >>>>> >>>>> On Wed, Oct 15, 2014 at 3:56 AM, Robert Lynn < >>>>> [email protected] >>>>> <javascript:_e(%7B%7D,'cvml','[email protected]');>> >>>>> wrote: >>>>> >>>>>> how do you know this? How do you know the the wire is not the >>>>>> brightest area? >>>>>> >>>>>> On 15 October 2014 15:06, H Veeder <[email protected] >>>>>> <javascript:_e(%7B%7D,'cvml','[email protected]');>> wrote: >>>>>> >>>>>>> Some people suspect that the resistor wire can't be Inconel because >>>>>>> they are predicted to melt at the reactor's operating temperature. >>>>>>> However, >>>>>>> since we know the resistor wire casts a shadow in the alumina, the >>>>>>> temperature of the wire remains below the operating temperature and >>>>>>> therefore can't melt. >>>>>>> >>>>>>> Harry >>>>>>> >>>>>> >>>>>> >>>>> >>>> >>> >> >
