I think that's a typo in the whitepaper. It should be (as you surmised): transform(X,B***A) = (X'',B'***A')
-Tad On Sat, Jul 10, 2010 at 12:40 PM, G <[email protected]> wrote: > Hi, > > I was reading through the OT whitepaper > athttp://wave-protocol.googlecode.com/hg/whitepapers/operational-transf.. > .. > Towards the end in the section on Composition, it says > > transform(X,A) = (X',A') > > and: > > transform(X',B) = (X'',B') > > implies: > > transform(X,B*A) = (X'',B*A') > > Does it mean to say transform(X,B.A) = (X'', B'.A') or is it really > (X'', B.A') as mentioned in the paper ? I am not able to visualise how > it can be B.A' instead of B'.A' and hence the question. Please > clarify. > > Gopa. > > -- > You received this message because you are subscribed to the Google Groups > "Wave Protocol" group. > To post to this group, send email to [email protected]. > To unsubscribe from this group, send email to > [email protected]<wave-protocol%[email protected]> > . > For more options, visit this group at > http://groups.google.com/group/wave-protocol?hl=en. > > -- You received this message because you are subscribed to the Google Groups "Wave Protocol" group. To post to this group, send email to [email protected]. To unsubscribe from this group, send email to [email protected]. For more options, visit this group at http://groups.google.com/group/wave-protocol?hl=en.
