Hi Gopa, Thanks for pointing that out. You're correct that it should indeed have said (X'', B'.A').
Beyond that, the white paper you looked at was rather out of date, and now we've just updated the white paper to be more current. The particular section you were referencing has disappeared, but will likely return in a different form in the future, as part of the plan to publish more detailed expositions regarding Wave OT. Best regards, Alex On 7/11/10, G <[email protected]> wrote: > Hi, > > I was reading through the OT whitepaper > athttp://wave-protocol.googlecode.com/hg/whitepapers/operational-transf.... > Towards the end in the section on Composition, it says > > transform(X,A) = (X',A') > > and: > > transform(X',B) = (X'',B') > > implies: > > transform(X,B*A) = (X'',B*A') > > Does it mean to say transform(X,B.A) = (X'', B'.A') or is it really > (X'', B.A') as mentioned in the paper ? I am not able to visualise how > it can be B.A' instead of B'.A' and hence the question. Please > clarify. > > Gopa. > > -- > You received this message because you are subscribed to the Google Groups > "Wave Protocol" group. > To post to this group, send email to [email protected]. > To unsubscribe from this group, send email to > [email protected]. > For more options, visit this group at > http://groups.google.com/group/wave-protocol?hl=en. > > -- You received this message because you are subscribed to the Google Groups "Wave Protocol" group. To post to this group, send email to [email protected]. To unsubscribe from this group, send email to [email protected]. For more options, visit this group at http://groups.google.com/group/wave-protocol?hl=en.
