The code where it does this is here--
if (strlen($cpassword)<5 || strlen($cpassword >16))
{
echo "Your password must be between 5 and 16 characters. Please go back
and try again.";
exit;
// check password length is ok
}
I tried printing the values of strlen before the if statement and it does give me 6
for the length of 123abc but it also gives me the error message saying "Your password
must be....."
I now realize that this is not the strlen problem. But What else could be going wrong
here?. I am checking that the user password is between 5 and 16 characters in length.
In this example if it is 6 it shouldn't be printing the message, but it does.
Anitha
>>> [EMAIL PROTECTED] 1/13/2004 11:50:16 AM >>>
Anitha Paruchuri wrote:
> Hi,
> I am trying to check the length of the password entered by the user
> using strlen($password). It works fine when say I enter a password as
> 'abc123' but if I entered '123abc' it somehow doesn't work fine. Am I
> missing something here? Should the $password or the variable for the
> function strlen() cannot start with a number??
>
Strings can be all digits. Do you have a sample of the code that doesn't
work? I've tested this and can't recreate the problem. Here's my test
script:
http://demo.fenelon.us/testCode/strlen_test.php?test3=43434
Change the value for test3 to try different strings.
Sheila
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