Yes, there are better ways. Instead of
def index():
return dict(link = A('clickme',_href=URL('plus_minus')))
def plus_minus():
do_something()
redirect(URL('index'))
You can do
def index():
return dict(link = A('clickme', callback=URL('plus_minus')))
def plus_minus():
do_something()
# no more redirect(URL('index'))
(and plus_minus will be called via ajax)
You can also do:
def index():
return dict(link = A('clickme',
callback=URL('plus_minus'),target='test'),
div = DIV(_id='test'))
def plus_minus():
do_something()
return "this text will go in target DIV#test"
so that you capture the response of the ajax too.
On Thursday, 6 December 2012 15:38:18 UTC-6, jonas wrote:
>
> hi
>
> I have a controller that basically inserts a number in a database. I don't
> want it to render any view. For now I just redirect back to index.html, but
> is there any other way to do it, i.e to have a controller that not renders
> any views?
>
> controller:
>
> def plus_minus():
>
> """ add or subtract likes """
>
> post=db(db.blog.id==request.args(0)).select().first()
> db.plus_minus.pm_id.default=post.id
> db.plus_minus.insert(plus=1)
> db.commit()
>
> redirect(URL('index'))
>
>
--
