how do you "fire" that function? If a user needs to go to that url
(/app/controller/plus_minus) than you have no other way than redirecting at
the end. If you want that function to be executed in another controller,
just do
def plus_minus(fakearg=0):
.....
and in your controller
def yourfunction():
....
plus_minus()
....
return dict(whatever=whatever)
The point is that a function with parameters can't be accessed by a user
going to the url.... i.e. /app/controller/plus_minus would return a 404
error.
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