I would suggest having the 'register' page take only one address, and after
creating, it redirects you to the 'view' of the client, which has a link to
a page where it shows all addresses and allows you to ADD an address. You
could also implement this in AJAX, which is what I would recommend.
Here's an example from one of my sites. I use it to save software to a
server.
$.post("scripts/newSoftware", // name of function to call
{
py_server: $("#serverid").val(),
py_guid: $("#guid").val(),
py_version: $("#version").val(),
py_who: $("#who").val(),
py_jobs: $("#jobs").val(),
py_comments: $("#comments").val()
}
,function(data) { $('#softwarelisting').load('onlysoftware?ID='+ data);}
);
On Monday, March 18, 2013 5:33:41 PM UTC-7, Alex Glaros wrote:
>
> Does anyone know how to create a loop allowing variable number of child
> records to be added to a parent?
>
> Here’s a sample where only one child is created. The “client” is the
> parent record and “address” is the child record.
> http://web2py.com/books/default/chapter/29/07
>
> Can anyone please type the code to show how to allow user to add variable
> number of child records?
>
> If it’s easier to do not using factory, that’s fine.
>
> Thanks,
>
> Alex Glaros
>
>
> One form for multiple tables
>
> model:
>
> db.define_table('client',
>
> Field('name'))
>
> db.define_table('address',
>
> Field('client','reference client',
>
> writable=False,readable=False),
>
> Field('street'),Field('city'))
>
> controller:
>
> def register():
>
> form=SQLFORM.factory(db.client,db.address)
>
> if form.process().accepted:
>
> id = db.client.insert(**db.client._filter_fields(form.vars))
>
> form.vars.client=id
>
> id = db.address.insert(**db.address._filter_fields(form.vars))
>
> response.flash='Thanks for filling the form'
>
> return dict(form=form)
>
>
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