Hi Derek, Thanks for you reply.
The key is, you want to submit via ajax, and make sure you do a 'return > false'. If there is an error in your javascript, you may see the post > getting sent to the current url or the action setting of the form. > At the moment I have a SQLFORM.factory() form which I return to the view in a dict. So there's no JavaScript involved yet, is there? What do I have to do to submit that form via ajax? Could you provide me with an example? Regards, Annet -- --- You received this message because you are subscribed to the Google Groups "web2py-users" group. To unsubscribe from this group and stop receiving emails from it, send an email to [email protected]. For more options, visit https://groups.google.com/groups/opt_out.
