Take a look here... http://www.web2py.com/book/default/chapter/11#Ajax-form-submission
On Friday, May 17, 2013 11:21:38 AM UTC-7, Annet wrote: > > Hi Derek, > > Thanks for you reply. > > The key is, you want to submit via ajax, and make sure you do a 'return >> false'. If there is an error in your javascript, you may see the post >> getting sent to the current url or the action setting of the form. >> > > At the moment I have a SQLFORM.factory() form which I return to the view > in a dict. So there's no JavaScript involved yet, is there? What do I have > to do to submit that form via ajax? Could you provide me with an example? > > > Regards, > > Annet > -- --- You received this message because you are subscribed to the Google Groups "web2py-users" group. To unsubscribe from this group and stop receiving emails from it, send an email to [email protected]. For more options, visit https://groups.google.com/groups/opt_out.
