How can I change from python the href value of SQLFORM.grid's back icon
button which is automatically added to the create/update/view form?
SQLFORM.grid sets the value to the referer's URL, but I ran into a
situation where that setting is grossly illogical, so I need to work around
the default setting.
For reference, the illogical setting comes about this way:
1. In start.html {{=LOAD(...start.load...ajax=True)}}
2. In start.load {{=grid_1}} which returns SQLFORM.grid(...)
3. grid_1 includes links to other.html?keywords=... (a search form), click
a link to go to other.html
4. In other.html {{=grid_2}}, that is another SQLFORM.grid without ajax
loading
5. Now, in the same browser tab, browse start.html
6. Click a row edit link in start.html which displays grid_1's update form
So far so good, but...
7. Click the back icon button in the update form; web2py puts you back into
other.html instead of start.html
So I want to work around web2py when it sets the href value of the back
icon button and set it to start.load as it should be
TIA
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