Maybe something like:
if request.args[-3] in ['view', 'edit']:
grid.element('[title=Back]').parent['_href'] = URL(...)
Anthony
On Friday, July 12, 2013 10:32:57 AM UTC-4, step wrote:
>
> How can I change from python the href value of SQLFORM.grid's back icon
> button which is automatically added to the create/update/view form?
> SQLFORM.grid sets the value to the referer's URL, but I ran into a
> situation where that setting is grossly illogical, so I need to work around
> the default setting.
>
> For reference, the illogical setting comes about this way:
> 1. In start.html {{=LOAD(...start.load...ajax=True)}}
> 2. In start.load {{=grid_1}} which returns SQLFORM.grid(...)
> 3. grid_1 includes links to other.html?keywords=... (a search form), click
> a link to go to other.html
> 4. In other.html {{=grid_2}}, that is another SQLFORM.grid without ajax
> loading
> 5. Now, in the same browser tab, browse start.html
> 6. Click a row edit link in start.html which displays grid_1's update form
> So far so good, but...
> 7. Click the back icon button in the update form; web2py puts you back
> into other.html instead of start.html
> So I want to work around web2py when it sets the href value of the back
> icon button and set it to start.load as it should be
>
> TIA
>
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