I think my question is simpler than appears. Can anyone answer this?
Instead of this:
def find_people_to_add_roles_and_relationships(): # this is the child
controller that gets called.
grid = SQLFORM.grid(db.auth_user, links=[dict(header='Add person to
role', body=lambda row: A('Assign person to role',_class="btn btn-success
btn-mini", _href=URL('assign_person_to_role', args=row.id,
vars=request.vars)))], links_placement = 'left')
I want
def find_people_to_add_roles_and_relationships(): # this is the child
controller that gets called.
grid = SQLFORM.grid(db.auth_user, links=[dict(header='Add person to
role', body=lambda row: A('Assign person to role',_class="btn btn-success
btn-mini", return or exit ( args=row.id, vars=request.vars)))],
links_placement = 'left')
thanks
Alex
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