there's a problem in your syntax.
it's usually URL('blabla', args=[], vars=dict())
while your code reports
args=[..., dict=()]
On Thursday, May 5, 2016 at 9:53:44 AM UTC+2, Paolo Amboni wrote:
>
> I stored the id in a session variable and it works fine!!
> But why the URL helper didn't send the args to the function?
>
> Il giorno giovedì 5 maggio 2016 09:36:32 UTC+2, Paolo Amboni ha scritto:
>>
>> I'm trying to build a single function (in a controller) that generate
>> different matplotlib graph..
>>
>> So the function that generate the stream works fine:
>> *def grafico*(title='title',xlab='x',ylab='y' data=.... ):
>> fig=Figure()
>> ....
>> return stream.getvalue()
>>
>>
>> the function that call the privious *works fine but not as i want:*
>>
>>
>> *def graf_comp_gior*():
>> test_id=1 # *I need to set the id on the fly*
>> print response.args # *Always none why?*
>> print response.vars #*Always none why?*
>>
>> rows = db(db.tat.id_test==test_id).select()
>> tat=pd.DataFrame(rows.as_list())
>> .... #manupulate the data as i need
>>
>> graf=grafico(........)
>>
>> return graf
>>
>> This is the view with the embedded graph works fine:
>>
>> {{{extend 'layout.html'}}
>> <h1>TAT completi per l'analisi {{=variabili['anal']}}</h1>
>> {{=IMG(_src=URL('graf_comp_gior',
>> *args=[argomenti[0],vars=dict('id'=argomenti[0])]))}} **How can i pass
>> some data to the previous function?*
>>
>> *Do i need to store them in a session?*
>> *Thanks!!*
>>
>
--
Resources:
- http://web2py.com
- http://web2py.com/book (Documentation)
- http://github.com/web2py/web2py (Source code)
- https://code.google.com/p/web2py/issues/list (Report Issues)
---
You received this message because you are subscribed to the Google Groups
"web2py-users" group.
To unsubscribe from this group and stop receiving emails from it, send an email
to [email protected].
For more options, visit https://groups.google.com/d/optout.
