thanks for detail explanation, anthony, tried your code but gave me different result *e.g.* *controllers/default.py* def sitemap(): request.extension = 'xml' or redirect(URL(extension = 'xml') ) return dict() #return locals()
access http://127.0.0.1:8000/a/default/sitemap *result* This XML file does not appear to have any style information associated with it. The document tree is shown below. <document/> btw, when it access with http://127.0.0.1:8000/a/default/sitemap.xml it return as expected *result* This XML file does not appear to have any style information associated with it. The document tree is shown below. <urlset xmlns="http://www.sitemaps.org/schemas/sitemap/0.9"; xmlns:image=" http://www.google.com/schemas/sitemap-image/1.1"xmlns:video="; http://www.google.com/schemas/sitemap-video/1.1";> <url> <loc>http://127.0.0.1:8000/a/default/user</loc> </url> <url> <loc>http://127.0.0.1:8000/a/default/index</loc> </url> <url> <loc>http://127.0.0.1:8000/a/default/sitemap</loc> </url> </urlset> any idea how to achieve it using web2py way? thanks and best regards, stifan -- Resources: - http://web2py.com - http://web2py.com/book (Documentation) - http://github.com/web2py/web2py (Source code) - https://code.google.com/p/web2py/issues/list (Report Issues) --- You received this message because you are subscribed to the Google Groups "web2py-users" group. To unsubscribe from this group and stop receiving emails from it, send an email to [email protected]. For more options, visit https://groups.google.com/d/optout.
