Assuming sqlite:
person_cnt =
db.PERSON_PROJECT_PRIORITY.person_fk.count().with_alias('person_cnt')
prioritySet = db((db.PERSON.id <http://db.person.id/> ==
PERSON-PROJECT-PRIORITY.person_fk) & (PROJECT.id ==
PERSON-PROJECT-PRIORITY.project_fk)).select(
...,
person_cnt,
'GROUP_CONCAT(person.person_name,",") AS person_list'
groupby = db.PERSON-PROJECT-PRIORITY.project_fk,
)
суббота, 14 ноября 2020 г. в 09:40:17 UTC+3, [email protected]:
> How to write a statement that counts which projects are the priority of
> most people
>
> PROJECT
> id
> project_name
>
> PERSON
> id
> person_name
>
> PERSON_PROJECT_PRIORITY
> person_fk
> project_fk
>
> prioritySet = db((db.PERSON.id == PERSON-PROJECT-PRIORITY.person_fk) &
> (PROJECT.id == PERSON-PROJECT-PRIORITY.project_fk)).select()
>
> How to sort by count of projects which have priority in order of the most
> persons' priority?
>
> Output looks like this:
>
> Paint-the-house (10) [Means is the top priority for 10 people]
> Plant-a-garden (5)
> Clean-out-garage (2)
>
> If you have additional time, how to write so output looks like:
>
> Paint-the-house (10) Tom, Sue, Tony, Ted, Mary, Fred, Sal, Chris, Ed, Sally
> Plant-a-garden (5) Harry, George, Joanne, Tony, Janet
> Clean-out-garage (2) Clyde, Jane
>
> Thanks,
>
> Alex Glaros
>
--
Resources:
- http://web2py.com
- http://web2py.com/book (Documentation)
- http://github.com/web2py/web2py (Source code)
- https://code.google.com/p/web2py/issues/list (Report Issues)
---
You received this message because you are subscribed to the Google Groups
"web2py-users" group.
To unsubscribe from this group and stop receiving emails from it, send an email
to [email protected].
To view this discussion on the web visit
https://groups.google.com/d/msgid/web2py/a8af9736-2dc8-4e93-99d4-95316f4cfc90n%40googlegroups.com.
