Just in case : pydal doesnt support backend specific aggregate functions

суббота, 14 ноября 2020 г. в 19:54:35 UTC+3, [email protected]: 

> There is no db.executesql
>
> суббота, 14 ноября 2020 г. в 19:51:52 UTC+3, [email protected]: 
>
>> sorry, did not mean direct SQL through db.executesql , meant through DAL
>>
>> On Saturday, November 14, 2020 at 8:23:11 AM UTC-8 [email protected] 
>> wrote:
>>
>>> Assuming sqlite:
>>> person_cnt = 
>>> db.PERSON_PROJECT_PRIORITY.person_fk.count().with_alias('person_cnt')
>>>
>>>
>>> prioritySet = db((db.PERSON.id <http://db.person.id/> == 
>>> PERSON-PROJECT-PRIORITY.person_fk) & (PROJECT.id == 
>>> PERSON-PROJECT-PRIORITY.project_fk)).select(
>>> ...,
>>> person_cnt, 
>>> 'GROUP_CONCAT(person.person_name,",") AS person_list'
>>> groupby = db.PERSON-PROJECT-PRIORITY.project_fk, 
>>> )
>>>
>>> суббота, 14 ноября 2020 г. в 09:40:17 UTC+3, [email protected]: 
>>>
>>>> How to write a statement that counts which projects are the priority of 
>>>> most people
>>>>
>>>> PROJECT
>>>> id
>>>> project_name
>>>>
>>>> PERSON
>>>> id
>>>> person_name
>>>>
>>>> PERSON_PROJECT_PRIORITY
>>>> person_fk
>>>> project_fk
>>>>
>>>> prioritySet = db((db.PERSON.id == PERSON-PROJECT-PRIORITY.person_fk) & 
>>>> (PROJECT.id == PERSON-PROJECT-PRIORITY.project_fk)).select()
>>>>
>>>> How to sort by count of projects which have priority in order of the 
>>>> most persons' priority?
>>>>
>>>> Output looks like this:
>>>>
>>>> Paint-the-house (10)  [Means is the top priority for 10 people]
>>>> Plant-a-garden (5)
>>>> Clean-out-garage (2)
>>>>
>>>> If you have additional time, how to write so output looks like:
>>>>
>>>> Paint-the-house (10) Tom, Sue, Tony, Ted, Mary, Fred, Sal, Chris, Ed, 
>>>> Sally
>>>> Plant-a-garden   (5) Harry, George, Joanne, Tony, Janet
>>>> Clean-out-garage (2) Clyde, Jane
>>>>
>>>> Thanks,
>>>>
>>>> Alex Glaros
>>>>
>>>

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