Hi,
I tried creating the url like this because it is in the view: {{=URL
(r=request,c='default', f='user', args='login')}} but it does not
work.
I used the jquery ajax method: jQuery.ajax("{{=URL
(r=request,c='default', f='user', args='login')}}", {},
success_callback, failure_callback);
I passed {} inplace of data.
On Sep 5, 11:55 pm, mdipierro <[email protected]> wrote:
> Yes the url is
>
> URL(r=request,c='default', f='user', args='login')
>
> or
>
> {{=URL(r=request,c='default', f='user', args='login')}}
>
> if in the view.
>
> On Sep 5, 1:48 pm, eddwinston <[email protected]> wrote:
>
> > Hi,
>
> > From the login form generated by web2py, if I intercept the submit
> > event so I can make an ajax request to the server, the request URL I
> > guess will be /[application]/user/login. Then what will be the
> > possible parameters?
>
> > Or should the request URL be something like this: URL(r=request,
> > c='default', f='user', args='login'). I am a bit confused
>
> > Regards,
> > Winston
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