Can you view the source on the page and verify that the URL is
correct?
On Sep 5, 7:23 pm, eddwinston <[email protected]> wrote:
> Hi mr freeze,
>
> My bad, I copied the wrong stuff in the previous post. This is
> actually how i did it:
> jQuery.ajax({
> type: "POST",
> url: "{{=URL(r=request,c='default', f='user', args='login'}}",
> data: {},
> success: success_callback,
> error: failure_callback
> });
>
> But it did not work.
>
> On Sep 6, 3:05 am, "mr.freeze" <[email protected]> wrote:
>
> > I don't think your options are set correctly. Try this:
>
> > jQuery.ajax({
> > type: "POST",
> > url: "{{=URL(r=request,c='default', f='user', args='login'}}",
> > data: {},
> > success: success_callback,
> > error: failure_callback
> > });
>
> > On Sep 5, 6:47 pm, eddwinston <[email protected]> wrote:
>
> > > Hi,
>
> > > I tried creating the url like this because it is in the view: {{=URL
> > > (r=request,c='default', f='user', args='login')}} but it does not
> > > work.
>
> > > I used the jquery ajax method: jQuery.ajax("{{=URL
> > > (r=request,c='default', f='user', args='login')}}", {},
> > > success_callback, failure_callback);
>
> > > I passed {} inplace of data.
>
> > > On Sep 5, 11:55 pm, mdipierro <[email protected]> wrote:
>
> > > > Yes the url is
>
> > > > URL(r=request,c='default', f='user', args='login')
>
> > > > or
>
> > > > {{=URL(r=request,c='default', f='user', args='login')}}
>
> > > > if in the view.
>
> > > > On Sep 5, 1:48 pm, eddwinston <[email protected]> wrote:
>
> > > > > Hi,
>
> > > > > From the login form generated by web2py, if I intercept the submit
> > > > > event so I can make an ajax request to the server, the request URL I
> > > > > guess will be /[application]/user/login. Then what will be the
> > > > > possible parameters?
>
> > > > > Or should the request URL be something like this: URL(r=request,
> > > > > c='default', f='user', args='login'). I am a bit confused
>
> > > > > Regards,
> > > > > Winston
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