You can simplify your code
def diag_form():
form = SQLFORM(db.socdiag, request.args(0), deletable=True)
if form.accepts(request.vars, session):
response.flash = 'form accepted'
elif form.errors:
# (1)
response.flash = 'form has errors'
return dict(form=form)
I am not sure what you asked. Try insert in (1)
form.vars.update(request.vars)
OR
if form.record: form.vars.update(form.record.as_dict())
OR
[form.vars[key]=db.socdiag[key].default for key in
db.socdiag.fields]
Does of them solves your problem?
On Jan 9, 5:12 pm, Jeff Bauer <[email protected]> wrote:
> I'm following another example in the manual using SQLFORM.
> The code works as advertised. The only fly in the ointment
> is when form.errors is True, the user's entry form no longer
> displays her original values. I'm assuming there's a simple
> way to pass the request vars back into form at line 11
> before return.
>
> 1 def diag_form():
> 2 if len(request.args):
> 3 records = db(db.socdiag.id==request.args[0]).select()
> 4 if len(request.args) and len(records):
> 5 form = SQLFORM(db.socdiag, records[0], deletable=True)
> 6 else:
> 7 form = SQLFORM(db.socdiag)
> 8 if form.accepts(request.vars, session):
> 9 response.flash = 'form accepted'
> 10 elif form.errors:
> 11 response.flash = 'form has errors'
> 12 return dict(form=form)
>
> Jeff Bauer
> Rubicon, Inc.
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