That is the default. Are you telling me it is not?

On Jan 9, 11:44 pm, Thadeus Burgess <[email protected]> wrote:
> like request.accept(keepvalues=True)... but only if there was an error.
>
> -Thadeus
>
> On Sat, Jan 9, 2010 at 11:32 PM, mdipierro <[email protected]> wrote:
> > You can simplify your code
>
> > def diag_form():
> >    form = SQLFORM(db.socdiag, request.args(0), deletable=True)
> >    if form.accepts(request.vars, session):
> >        response.flash = 'form accepted'
> >    elif form.errors:
> >        # (1)
> >        response.flash = 'form has errors'
> >    return dict(form=form)
>
> > I am not sure what you asked. Try insert in (1)
>
> >   form.vars.update(request.vars)
>
> > OR
>
> >   if form.record: form.vars.update(form.record.as_dict())
>
> > OR
>
> >   [form.vars[key]=db.socdiag[key].default for key in
> > db.socdiag.fields]
>
> > Does of them solves your problem?
>
> > On Jan 9, 5:12 pm, Jeff Bauer <[email protected]> wrote:
> >> I'm following another example in the manual using SQLFORM.
> >> The code works as advertised.  The only fly in the ointment
> >> is when form.errors is True, the user's entry form no longer
> >> displays her original values.  I'm assuming there's a simple
> >> way to pass the request vars back into form at line 11
> >> before return.
>
> >>   1 def diag_form():
> >>   2    if len(request.args):
> >>   3        records = db(db.socdiag.id==request.args[0]).select()
> >>   4    if len(request.args) and len(records):
> >>   5        form = SQLFORM(db.socdiag, records[0], deletable=True)
> >>   6    else:
> >>   7        form = SQLFORM(db.socdiag)
> >>   8    if form.accepts(request.vars, session):
> >>   9        response.flash = 'form accepted'
> >> 10    elif form.errors:
> >> 11        response.flash = 'form has errors'
> >> 12    return dict(form=form)
>
> >> Jeff Bauer
> >> Rubicon, Inc.
>
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