In Version 1.83.2 (2010-08-15 02:10:01) this works:
{{
for r in rows:
=DIV(SPAN(r[0]), SPAN(fcw[r[0]]), SPAN(fcw[r[1]]))
pass
}}
but this raises a syntax error:
{{
for r in rows:
=DIV(SPAN(r[0]),
SPAN(fcw[r[0]]),
SPAN(fcw[r[1]]))
pass
}}
Tried '\' continuations also. The parser thinks there are extra chars
after the backslash even when there aren't.
Apologies if this is a known issue or intentional limitation.
Cheers,
Mike

