In Version 1.83.2 (2010-08-15 02:10:01)

this works:

{{
for r in rows:
    =DIV(SPAN(r[0]), SPAN(fcw[r[0]]), SPAN(fcw[r[1]]))
    pass
}}

but this raises a syntax error:
{{
for r in rows:
    =DIV(SPAN(r[0]),
      SPAN(fcw[r[0]]),
      SPAN(fcw[r[1]]))
    pass
}}

Tried '\' continuations also.  The parser thinks there are extra chars
after the backslash even when there aren't.

Apologies if this is a known issue or intentional limitation.

Cheers,
Mike

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