Did this work before? I do not think continuation was ever supported. Massimo
On Aug 22, 2:13 pm, Michael Ellis <[email protected]> wrote: > In Version 1.83.2 (2010-08-15 02:10:01) > > this works: > > {{ > for r in rows: > =DIV(SPAN(r[0]), SPAN(fcw[r[0]]), SPAN(fcw[r[1]])) > pass > > }} > > but this raises a syntax error: > {{ > for r in rows: > =DIV(SPAN(r[0]), > SPAN(fcw[r[0]]), > SPAN(fcw[r[1]])) > pass > > }} > > Tried '\' continuations also. The parser thinks there are extra chars > after the backslash even when there aren't. > > Apologies if this is a known issue or intentional limitation. > > Cheers, > Mike
