anybody?????????
On Jul 27, 2011 1:02 PM, "Ismael Serratos" <[email protected]> wrote:
> I found this for Django I need exactly the same but for web2py could you
> help me to translate??? or to give me a hint?
>
> # --------- upload_file.py ----------------# upload binary file with
> pycurl by http postc = pycurl.Curl()c.setopt(c.POST, 1)c.setopt(c.URL,
> "http://127.0.0.1:8000/receive/";)c.setopt(c.HTTPPOST, [("file1",
> (c.FORM_FILE, "c:\\tmp\\download\\test.jpg"))])#c.setopt(c.VERBOSE,
> 1)c.perform()c.close()print "that's it ;)"
> # --------------------------------# DJANGO RECEIVE TEST APPLICATION#
> --------------------------------
> # --------- urls.py ----------------from django.conf.urls.defaults
> import *urlpatterns = patterns('',
> (r'^receive/$', 'web.views.receive'),
> )
> # --------- web\views.py ----------------def receive(request):
> assert request.method=="POST"
> print "receive.META.SERVER_PORT", request.META["SERVER_PORT"],
request.POST
> files = []
> for multipart_name in request.FILES.keys():
> multipart_obj = request.FILES[multipart_name]
> content_type = multipart_obj['content-type']
> filename = multipart_obj['filename']
> content = multipart_obj['content']
> files.append((filename, content_type, content))
> import datetime
> # write file to the system - add timestamp in the name
> file("c:\\tmp\\%s_%s" %
> (datetime.datetime.now().isoformat().replace(":", "-"), filename),
> "wb").write(content)
>
> fnames = ",".join([fname for fname, ct, c in files])
> return HttpResponse("me-%s-RECEIVE-OK[POST=%s,files=%s]" %
> (request.META["SERVER_PORT"], request.POST.values(), fnames ))
>
>
>
> On Wed, Jul 27, 2011 at 11:57 AM, pbreit <[email protected]> wrote:
>
>> The problem with SQLFORM is that I think it's going to be expecting a
>> hidden field for security purposes. You might need to just write a
>> controller that processes request.post_vars.myfile manually.
